What is the solution for x^{'''}+x^{''}=0 ?

The solution for x^{'''}+x^{''}=0 is x=c_{1}e^{-t}+c_{2}+c_{3}t

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x^{'''}+x^{''}=0

x^{^{'''}} + x^{^{''}} = 0

x = c_{1} e^{- t} + c_{2} + c_{3} t

Solution steps

x^{'''} (t) + x^{''} (t) = 0

Solve linear ODE:

x = c_{1} e^{- t} + c_{2} + c_{3} t

x = c_{1} e^{- t} + c_{2} + c_{3} t

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\int sin^{2} (5 x) cos^{2} (5 x) d x

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\frac{d}{d x} (\frac{e ^{x}}{1 + e ^{x}})

3 e^{5 x} \frac{d y}{d x} = - 25 \frac{x}{y ^{2}}

What is the solution for x^{'''}+x^{''}=0 ?
The solution for x^{'''}+x^{''}=0 is x=c_{1}e^{-t}+c_{2}+c_{3}t