What is the integral from 1 to 3 of-7/(x^2) ?

The integral from 1 to 3 of-7/(x^2) is -14/3

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integral from 1 to 3 of-7/(x^2)

\int_{1}^{3} - \frac{7}{x ^{2}} d x

- \frac{14}{3}

Decimal Notation

- 4.66666 \dots

Solution steps

\int_{1}^{3} - \frac{7}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 7 \cdot \int_{1}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{3}

= - 7 [- \frac{1}{x}]_{1}^{3}

Compute the boundaries:

\frac{2}{3}

= - 7 \cdot \frac{2}{3}

Simplify

= - \frac{14}{3}

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What is the integral from 1 to 3 of-7/(x^2) ?
The integral from 1 to 3 of-7/(x^2) is -14/3