What is the integral from 0 to 2 of p^2sin(x) ?

The integral from 0 to 2 of p^2sin(x) is sin(x) 8/3

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integral from 0 to 2 of p^2sin(x)

\int_{0}^{2} p^{2} sin (x) d p

sin (x) \frac{8}{3}

Solution steps

\int_{0}^{2} p^{2} sin (x) d p

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (x) \cdot \int_{0}^{2} p^{2} d p

Apply the Power Rule

: [\frac{p ^{3}}{3}]_{0}^{2}

= sin (x) [\frac{p ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= sin (x) \frac{8}{3}

\int_{0}^{2} 9 x e^{- 3 x} d x

\int_{0}^{2} \frac{1}{9 x ^{2} + 36} d x

\int_{2}^{5} 2 x - 1 d x

\int_{0}^{1} \frac{3 y ^{2}}{4 + y ^{3}} d y

\int_{2}^{3} \frac{4 t}{1 + t ^{2}} d t

What is the integral from 0 to 2 of p^2sin(x) ?
The integral from 0 to 2 of p^2sin(x) is sin(x) 8/3