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Popular >

integral from 0 to 6 of (x^2+x+1)

Solution

\int_{0}^{6} (x^{2} + x + 1) d x

Solution

96

Solution steps

\int_{0}^{6} x^{2} + x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} x^{2} d x + \int_{0}^{6} x d x + \int_{0}^{6} 1 d x

\int_{0}^{6} x^{2} d x = 72

\int_{0}^{6} x d x = 18

\int_{0}^{6} 1 d x = 6

= 72 + 18 + 6

Simplify

= 96

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\int_{1}^{5} x^{3} + 8 x - 4 d x

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\int_{3}^{4} 2 x^{2} d x

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\int_{0}^{1} \frac{1}{100 + x ^{2}} d x

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\int_{1}^{16} 2 x^{- \frac{3}{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 6 of (x^2+x+1) ?
The integral from 0 to 6 of (x^2+x+1) is 96