What is the integral from 1 to x^3 of e^{t^2} ?

The integral from 1 to x^3 of e^{t^2} is (sqrt(pi))/2 \erfi(x^3)-(sqrt(pi))/2 \erfi(1)

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integral from 1 to x^3 of e^{t^2}

\int_{1}^{x^{3}} e^{t^{2}} d t

\frac{π}{2} erfi (x^{3}) - \frac{π}{2} erfi (1)

Solution steps

\int_{1}^{x^{3}} e^{t^{2}} d t

Use the nonelementary integral:

\int e^{t^{2}} d t = \frac{π}{2} erfi (t)

= [\frac{π}{2} erfi (t)]_{1}^{x^{3}}

Compute the boundaries:

\frac{π}{2} erfi (x^{3}) - \frac{π}{2} erfi (1)

= \frac{π}{2} erfi (x^{3}) - \frac{π}{2} erfi (1)

\int_{0}^{e - 1} x ln (x + 1) d x

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\int_{8}^{10} \frac{x}{8} - \frac{8}{x} d x

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What is the integral from 1 to x^3 of e^{t^2} ?
The integral from 1 to x^3 of e^{t^2} is (sqrt(pi))/2 \erfi(x^3)-(sqrt(pi))/2 \erfi(1)