What is the derivative of 2(x-2^2) ?

The derivative of 2(x-2^2) is 4(x-2)

What is the first derivative of 2(x-2^2) ?

The first derivative of 2(x-2^2) is 4(x-2)

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\frac{d}{d x} (2 (x - 2)^{2})

4 (x - 2)

Solution steps

\frac{d}{d x} (2 (x - 2)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((x - 2)^{2})

Apply the chain rule:

2 (x - 2) \frac{d}{d x} (x - 2)

= 2 (x - 2) \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 2 \cdot 2 (x - 2) \cdot 1

Simplify

= 4 (x - 2)

sin^{2} (2 t)

\int ln (x - 3) d x

f (x) = \frac{2}{x - 5}, at x = 7

\int (x^{2} + 1) (4 x - 3) d x

\int \frac{4 x ^{3}}{1 - x ^{4}} d x

What is the derivative of 2(x-2^2) ?
The derivative of 2(x-2^2) is 4(x-2)
What is the first derivative of 2(x-2^2) ?
The first derivative of 2(x-2^2) is 4(x-2)