What is the integral from-4 to 4 of (x^2-16) ?

The integral from-4 to 4 of (x^2-16) is -256/3

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integral from-4 to 4 of (x^2-16)

\int_{- 4}^{4} (x^{2} - 16) d x

- \frac{256}{3}

Decimal

- 85.33333 \dots

Solution steps

\int_{- 4}^{4} x^{2} - 16 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 4}^{4} x^{2} d x - \int_{- 4}^{4} 16 d x

\int_{- 4}^{4} x^{2} d x = \frac{128}{3}

\int_{- 4}^{4} 16 d x = 128

= \frac{128}{3} - 128

Simplify

\frac{128}{3} - 128 : - \frac{256}{3}

= - \frac{256}{3}

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What is the integral from-4 to 4 of (x^2-16) ?
The integral from-4 to 4 of (x^2-16) is -256/3