What is the integral from 0 to 0 of sqrt(36-x^2) ?

The integral from 0 to 0 of sqrt(36-x^2) is 0

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integral from 0 to 0 of sqrt(36-x^2)

\int_{0}^{0} 36 - x^{2} d x

0

Solution steps

\int_{0}^{0} 36 - x^{2} d x

\int_{a}^{a} f (x) d x = 0, a \neq = \infty

= 0

\int_{- 1}^{2} (x^{4} - x^{5}) d x

\int_{0}^{\frac{π}{16}} sec^{2} (4 x) d x

\int_{0}^{\frac{1}{2}} \frac{1}{x - x ^{2}} d x

\int_{- \infty}^{2} θ e^{θ} d θ

\int_{- 5}^{2} (2 x + 4) d x

What is the integral from 0 to 0 of sqrt(36-x^2) ?
The integral from 0 to 0 of sqrt(36-x^2) is 0