What is the integral from 0 to 1 of ye^{-y} ?

The integral from 0 to 1 of ye^{-y} is -2/e+1

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integral from 0 to 1 of ye^{-y}

\int_{0}^{1} y e^{- y} d y

- \frac{2}{e} + 1

Decimal

0.26424 \dots

Solution steps

\int_{0}^{1} y e^{- y} d y

Apply Integration By Parts

: [- e^{- y} y - \int - e^{- y} d y]_{0}^{1}

= [- e^{- y} y - \int - e^{- y} d y]_{0}^{1}

\int - e^{- y} d y = e^{- y}

= [- e^{- y} y - e^{- y}]_{0}^{1}

Compute the boundaries:

- \frac{2}{e} + 1

= - \frac{2}{e} + 1

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What is the integral from 0 to 1 of ye^{-y} ?
The integral from 0 to 1 of ye^{-y} is -2/e+1