What is the integral from 0 to infinity of 1/y ?

The integral from 0 to infinity of 1/y is diverges

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integral from 0 to infinity of 1/y

\int_{0}^{\infty} \frac{1}{y} d y

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{y} d y

Compute the indefinite integral:

\int \frac{1}{y} d y = ln ∣ y ∣ + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{y} d y =

diverges

= diverges

\int_{0}^{400} x d x

\int_{- 1}^{x} \frac{1}{3} d x

\int_{4}^{8} \frac{1}{64 - x ^{2}} d x

\int_{0}^{0.4} x^{2} (1 - x)^{2} d x

\int_{- 1}^{3} 2 x + 8 d x

What is the integral from 0 to infinity of 1/y ?
The integral from 0 to infinity of 1/y is diverges