What is the integral from 0 to 1 of 3/(x^4) ?

The integral from 0 to 1 of 3/(x^4) is diverges

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integral from 0 to 1 of 3/(x^4)

\int_{0}^{1} \frac{3}{x ^{4}} d x

diverges

Solution steps

\int_{0}^{1} \frac{3}{x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} \frac{1}{x ^{4}} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{0}^{1}

= 3 [- \frac{1}{3 x ^{3}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

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What is the integral from 0 to 1 of 3/(x^4) ?
The integral from 0 to 1 of 3/(x^4) is diverges