What is the integral from 0 to 49 of sqrt(x) ?

The integral from 0 to 49 of sqrt(x) is 686/3

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integral from 0 to 49 of sqrt(x)

\int_{0}^{49} x d x

\frac{686}{3}

Decimal

228.66666 \dots

Solution steps

\int_{0}^{49} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{49}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{49}

Compute the boundaries:

\frac{686}{3}

= \frac{686}{3}

\int_{0}^{2} x^{2} + 3 x - 3 d x

\int_{0}^{1} 2 x (5 - x^{2}) d x

\int_{- 1}^{2} x^{2} + 2 - sin (x) d x

\int_{0}^{t} 18 e^{5 x} d x

\int_{0}^{1} 4 (1 - x)^{3} d x

What is the integral from 0 to 49 of sqrt(x) ?
The integral from 0 to 49 of sqrt(x) is 686/3