What is the integral from-1 to 1 of sin(2x)+cos(3x) ?

The integral from-1 to 1 of sin(2x)+cos(3x) is 2/3 sin(3)

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integral from-1 to 1 of sin(2x)+cos(3x)

\int_{- 1}^{1} sin (2 x) + cos (3 x) d x

\frac{2}{3} sin (3)

Decimal

0.09408 \dots

Solution steps

\int_{- 1}^{1} sin (2 x) + cos (3 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} sin (2 x) d x + \int_{- 1}^{1} cos (3 x) d x

\int_{- 1}^{1} sin (2 x) d x = 0

\int_{- 1}^{1} cos (3 x) d x = \frac{2}{3} sin (3)

= 0 + \frac{2}{3} sin (3)

Simplify

= \frac{2}{3} sin (3)

\int_{1}^{2} 4 e^{3 x - 2} d x

\int_{3}^{10} 1

\int_{- 1}^{4} 2 x + 4 d x

\int_{1}^{4} \frac{ln ( x )}{x ^{3}} d x

\int_{0}^{l n (2)} 6 e^{2 t} d t

What is the integral from-1 to 1 of sin(2x)+cos(3x) ?
The integral from-1 to 1 of sin(2x)+cos(3x) is 2/3 sin(3)