What is the integral from 1 to 16 of (x^{-9/4}) ?

The integral from 1 to 16 of (x^{-9/4}) is 31/40

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integral from 1 to 16 of (x^{-9/4})

\int_{1}^{16} (x^{- \frac{9}{4}}) d x

\frac{31}{40}

Decimal

0.775

Solution steps

\int_{1}^{16} x^{- \frac{9}{4}} d x

Apply the Power Rule

: [- \frac{4}{5 x ^{\frac{5}{4}}}]_{1}^{16}

= [- \frac{4}{5 x ^{\frac{5}{4}}}]_{1}^{16}

Compute the boundaries:

\frac{31}{40}

= \frac{31}{40}

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What is the integral from 1 to 16 of (x^{-9/4}) ?
The integral from 1 to 16 of (x^{-9/4}) is 31/40