What is the integral from 0 to pi/2 of 7sin(x) ?

The integral from 0 to pi/2 of 7sin(x) is 7

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integral from 0 to pi/2 of 7sin(x)

\int_{0}^{\frac{π}{2}} 7 sin (x) d x

7

Solution steps

\int_{0}^{\frac{π}{2}} 7 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{0}^{\frac{π}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 7 [- cos (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 7 \cdot 1

Simplify

= 7

\int_{0}^{0.5} (\frac{sin ( 3 x )}{x}) d x

\int_{2}^{4} \frac{3}{2 x + 1} d x

\int_{- 4}^{0} 4 d x

\int_{- 2}^{0} 8 x + 2 x^{2} - x^{3} d x

\int_{0}^{6} x^{2} - 4 x d x

What is the integral from 0 to pi/2 of 7sin(x) ?
The integral from 0 to pi/2 of 7sin(x) is 7