What is the integral from 0 to-1 of x^2 ?

The integral from 0 to-1 of x^2 is -1/3

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integral from 0 to-1 of x^2

\int_{0}^{- 1} x^{2} d x

- \frac{1}{3}

Decimal

- 0.33333 \dots

Solution steps

\int_{0}^{- 1} x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 1}^{0} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{0}

= - [\frac{x ^{3}}{3}]_{- 1}^{0}

Compute the boundaries:

\frac{1}{3}

= - \frac{1}{3}

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What is the integral from 0 to-1 of x^2 ?
The integral from 0 to-1 of x^2 is -1/3