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Popular >

integral from 2 to 4 of (16-x^2)

Solution

\int_{2}^{4} (16 - x^{2}) d x

Solution

\frac{40}{3}

+1

Decimal

13.33333 \dots

Solution steps

\int_{2}^{4} 16 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} 16 d x - \int_{2}^{4} x^{2} d x

\int_{2}^{4} 16 d x = 32

\int_{2}^{4} x^{2} d x = \frac{56}{3}

= 32 - \frac{56}{3}

Simplify

32 - \frac{56}{3} : \frac{40}{3}

= \frac{40}{3}

Graph

Popular Examples

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\int_{0}^{1} e^{3 x^{3}} d x

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\int_{\frac{π}{4}}^{\frac{π}{3}} \frac{1}{sin ( x )} d x

integral from-3 to 6 of | 1/2 x|

\int_{- 3}^{6} \frac{1}{2} x d x

integral from 0 to 2 of (5)

\int_{0}^{2} (5) d x

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\int_{e^{2}}^{e^{6}} 5 t^{- 1} d t

Frequently Asked Questions (FAQ)

What is the integral from 2 to 4 of (16-x^2) ?
The integral from 2 to 4 of (16-x^2) is 40/3