What is the integral from 1 to 2 of 6 ?

The integral from 1 to 2 of 6 is 6

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integral from 1 to 2 of 6

\int_{1}^{2} 6 d x

6

Solution steps

\int_{1}^{2} 6 d x

Integral of a constant:

\int a d x = a x

= [6 x]_{1}^{2}

Compute the boundaries:

6

= 6

\int_{0}^{1} \frac{x ^{2}}{3 + x ^{2}} d x

\int_{0}^{1} (2 x - \frac{x}{2}) d x

\int_{- 8}^{8} 1 d x

\int_{1}^{x} \frac{4}{x ^{5}} d x

\int_{0}^{1} 9 x^{8} (6 - x^{9}) d x