What is the integral from-1 to 1 of x(x+1)(x-1) ?

The integral from-1 to 1 of x(x+1)(x-1) is 0

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integral from-1 to 1 of x(x+1)(x-1)

\int_{- 1}^{1} x (x + 1) (x - 1) d x

0

Solution steps

\int_{- 1}^{1} x (x + 1) (x - 1) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x (x + 1) (x - 1) :

Odd

= 0

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\int_{0}^{2} - 2 x^{2} d x

\int_{b}^{a} \frac{x - y}{x + y} d y

\int_{1}^{2} 25 - (x - 5)^{2} d x

What is the integral from-1 to 1 of x(x+1)(x-1) ?
The integral from-1 to 1 of x(x+1)(x-1) is 0