What is the integral from-pi to pi of t/(1+cos(t)) ?

The integral from-pi to pi of t/(1+cos(t)) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-pi to pi of t/(1+cos(t))

\int_{- π}^{π} \frac{t}{1 + cos ( t )} d t

0

Solution steps

\int_{- π}^{π} \frac{t}{1 + cos ( t )} d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{t}{1 + cos ( t )} :

Odd

= 0

\int_{3}^{6} 6 d x

\int_{1}^{2} (x^{3} + 3) d x

\int_{3}^{6} 5 d x

\int_{0}^{4} 3 x + 5 d x

\int_{1}^{2} (28 x^{3} + \frac{6}{x ^{2}}) d x

What is the integral from-pi to pi of t/(1+cos(t)) ?
The integral from-pi to pi of t/(1+cos(t)) is 0