What is (\partial)/(\partial x)(ln(4x^2)) ?

The answer to (\partial)/(\partial x)(ln(4x^2)) is 2/x

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(\partial)/(\partial x)(ln(4x^2))

\frac{\partial}{\partial x} (ln (4 x^{2}))

\frac{2}{x}

Solution steps

\frac{\partial}{\partial x} (ln (4 x^{2}))

Apply the chain rule:

\frac{1}{4 x ^{2}} \frac{\partial}{\partial x} (4 x^{2})

= \frac{1}{4 x ^{2}} \frac{\partial}{\partial x} (4 x^{2})

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

= \frac{1}{4 x ^{2}} \cdot 8 x

Simplify

\frac{1}{4 x ^{2}} \cdot 8 x : \frac{2}{x}

= \frac{2}{x}

\frac{d ^{2}}{d x ^{2}} (e^{x} sin (x))

\int e^{\frac{t}{50}} d t

\int_{1}^{2} \frac{( x + 1 ) ^{2}}{x} d x

\frac{d}{d x} (x (ln (x))^{2})

\int \frac{ln ( x ) - 1}{( ln ( x ) ) ^{2}} d x

What is (\partial)/(\partial x)(ln(4x^2)) ?
The answer to (\partial)/(\partial x)(ln(4x^2)) is 2/x