What is the integral from 0 to 4 of 9x^2 ?

The integral from 0 to 4 of 9x^2 is 192

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integral from 0 to 4 of 9x^2

\int_{0}^{4} 9 x^{2} d x

192

Solution steps

\int_{0}^{4} 9 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= 9 [\frac{x ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= 9 \cdot \frac{64}{3}

Simplify

= 192

\int_{0}^{y} \frac{6 ( y - x )}{8} d x

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\int_{0}^{9} 2 x + 9 d x

\int_{0}^{1} x^{2} (2 x^{3} + 3)^{2} d x

What is the integral from 0 to 4 of 9x^2 ?
The integral from 0 to 4 of 9x^2 is 192