What is the integral from 1 to 2 of sqrt(1) ?

The integral from 1 to 2 of sqrt(1) is 1

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integral from 1 to 2 of sqrt(1)

\int_{1}^{2} 1

1

Solution steps

\int_{1}^{2} 1 d x

Integral of a constant:

\int a d x = a x

= [1 x]_{1}^{2}

Simplify

= [x]_{1}^{2}

Compute the boundaries:

1

= 1

\int_{- 2}^{2} 1 - \frac{x ^{2}}{4} d x

\int_{1}^{4} (x^{2} + 6) d x

\int_{3}^{x^{2}} \frac{1}{t ^{4}} d t

\int_{- 1}^{1} x^{2} + x + 2 d x

\int_{- 1}^{1} x - 3 + \frac{1}{x - 2} d x

What is the integral from 1 to 2 of sqrt(1) ?
The integral from 1 to 2 of sqrt(1) is 1