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Popular >

integral from-1 to 2 of-x^2-x+8

Solution

\int_{- 1}^{2} - x^{2} - x + 8 d x

Solution

\frac{39}{2}

+1

Decimal

19.5

Solution steps

\int_{- 1}^{2} - x^{2} - x + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{2} x^{2} d x - \int_{- 1}^{2} x d x + \int_{- 1}^{2} 8 d x

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 8 d x = 24

= - 3 - \frac{3}{2} + 24

Simplify

- 3 - \frac{3}{2} + 24 : \frac{39}{2}

= \frac{39}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of-x^2-x+8 ?
The integral from-1 to 2 of-x^2-x+8 is 39/2