What is the tangent of y=x^3-2x+1,(2,5) ?

The tangent of y=x^3-2x+1,(2,5) is y=10x-15

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tangent of y=x^3-2x+1,(2,5)

tangent of

y = x^{3} - 2 x + 1, (2, 5)

y = 10 x - 15

Solution steps

Find the slope of

y = x^{3} - 2 x + 1 : \frac{d y}{d x} = 3 x^{2} - 2

Compute the slope of

y = x^{3} - 2 x + 1

(2, 5) : m = 10

Find the line with slope m=

10

and passing through

(2, 5) : y = 10 x - 15

y = 10 x - 15

\int_{- 2}^{1} ∣ x ∣ d x

\frac{d y}{d x} + a y = b

\int \frac{x ^{3}}{( 7 - x ^{4} ) ^{5}} d x

\frac{\partial}{\partial x} (e^{x (e^{y})})

2 (x - 2) - cos (3 x) \cdot 3

What is the tangent of y=x^3-2x+1,(2,5) ?
The tangent of y=x^3-2x+1,(2,5) is y=10x-15