What is the integral from-3 to 0 of g(t) ?

The integral from-3 to 0 of g(t) is -(9g)/2

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integral from-3 to 0 of g(t)

\int_{- 3}^{0} g (t) d t

- \frac{9 g}{2}

Solution steps

\int_{- 3}^{0} g t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{- 3}^{0} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{- 3}^{0}

= g [\frac{t ^{2}}{2}]_{- 3}^{0}

Compute the boundaries:

- \frac{9}{2}

= g (- \frac{9}{2})

Simplify

= - \frac{9 g}{2}

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What is the integral from-3 to 0 of g(t) ?
The integral from-3 to 0 of g(t) is -(9g)/2