What is the integral from 1 to 2 of (3x^2+4x+1) ?

The integral from 1 to 2 of (3x^2+4x+1) is 14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of (3x^2+4x+1)

\int_{1}^{2} (3 x^{2} + 4 x + 1) d x

14

Solution steps

\int_{1}^{2} 3 x^{2} + 4 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} 4 x d x + \int_{1}^{2} 1 d x

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} 4 x d x = 6

\int_{1}^{2} 1 d x = 1

= 7 + 6 + 1

Simplify

= 14

\int_{0}^{4} \frac{1}{3 x + 5} d x

\int_{0}^{2} x^{3} (4 - x^{2}) d x

\int_{2}^{10} e^{x} d x

\int_{0}^{\frac{7}{3}} \frac{1}{9 x ^{2} + 49} d x

\int_{- 3}^{3} 81 - x^{4} d x

What is the integral from 1 to 2 of (3x^2+4x+1) ?
The integral from 1 to 2 of (3x^2+4x+1) is 14