What is the integral from (3pi)/2 to 2pi of cos(θ) ?

The integral from (3pi)/2 to 2pi of cos(θ) is 1

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integral from (3pi)/2 to 2pi of cos(θ)

\int_{\frac{3 π}{2}}^{2 π} cos (θ) d θ

1

Solution steps

\int_{\frac{3 π}{2}}^{2 π} cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= [sin (θ)]_{\frac{3 π}{2}}^{2 π}

Compute the boundaries:

1

= 1

\int_{- 1}^{0} \frac{1}{2 + x} d x

\int_{1}^{3} \frac{2 x}{x ^{2} + 3} d x

\int_{0}^{5} cos (\frac{nπ x}{5}) d x

\int_{- 1}^{3} 4 x - 3 d x

\int_{- 1}^{6} 3 d x

What is the integral from (3pi)/2 to 2pi of cos(θ) ?
The integral from (3pi)/2 to 2pi of cos(θ) is 1