What is the integral from 0 to x^2 of cos(t) ?

The integral from 0 to x^2 of cos(t) is sin(x^2)

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integral from 0 to x^2 of cos(t)

\int_{0}^{x^{2}} cos (t) d t

sin (x^{2})

Solution steps

\int_{0}^{x^{2}} cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= [sin (t)]_{0}^{x^{2}}

Compute the boundaries:

sin (x^{2})

= sin (x^{2})

\int_{- 4}^{1} (- x^{2} - 3 x) d x

\int_{0}^{1} (x + 1) (x^{2} + 2 x)^{2} d x

\int_{- 1}^{1} (\frac{5}{x ^{2} + 1}) d x

\int_{0}^{4} sin^{2} (x) d x

\int_{- \infty}^{3} 4^{x} d x

What is the integral from 0 to x^2 of cos(t) ?
The integral from 0 to x^2 of cos(t) is sin(x^2)