What is the integral from-1 to 2 of sqrt(x^2) ?

The integral from-1 to 2 of sqrt(x^2) is 5/2

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integral from-1 to 2 of sqrt(x^2)

\int_{- 1}^{2} x^{2} d x

\frac{5}{2}

Decimal

2.5

Solution steps

\int_{- 1}^{2} x^{2} d x

Apply exponent rule:

a^{2} = ∣ a ∣

= \int_{- 1}^{2} ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 1}^{0} - x d x + \int_{0}^{2} x d x

\int_{- 1}^{0} - x d x = \frac{1}{2}

\int_{0}^{2} x d x = 2

= \frac{1}{2} + 2

Simplify

\frac{1}{2} + 2 : \frac{5}{2}

= \frac{5}{2}

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What is the integral from-1 to 2 of sqrt(x^2) ?
The integral from-1 to 2 of sqrt(x^2) is 5/2