What is the integral from-1 to 1 of 6tsqrt(4t^2+1) ?

The integral from-1 to 1 of 6tsqrt(4t^2+1) is 0

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integral from-1 to 1 of 6tsqrt(4t^2+1)

\int_{- 1}^{1} 6 t 4 t^{2} + 1 d t

0

Solution steps

\int_{- 1}^{1} 6 t 4 t^{2} + 1 d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

6 t 4 t^{2} + 1 :

Odd

= 0

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What is the integral from-1 to 1 of 6tsqrt(4t^2+1) ?
The integral from-1 to 1 of 6tsqrt(4t^2+1) is 0