What is the integral from 0 to x^2 of y ?

The integral from 0 to x^2 of y is (x^4)/2

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integral from 0 to x^2 of y

\int_{0}^{x^{2}} y d y

\frac{x ^{4}}{2}

Solution steps

\int_{0}^{x^{2}} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{x^{2}}

= [\frac{y ^{2}}{2}]_{0}^{x^{2}}

Compute the boundaries:

\frac{x ^{4}}{2}

= \frac{x ^{4}}{2}

\int_{- 5}^{8} x^{2} d x

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\int_{0}^{2} (x) 2^{4 x^{2}} d x

What is the integral from 0 to x^2 of y ?
The integral from 0 to x^2 of y is (x^4)/2