What is the integral from 0 to \sqrt[3]{10 of}x^2 ?

The integral from 0 to \sqrt[3]{10 of}x^2 is 10/3

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integral from 0 to \sqrt[3]{10 of}x^2

\int_{0}^{310} x^{2} d x

\frac{10}{3}

Decimal

3.33333 \dots

Solution steps

\int_{0}^{310} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{310}

= [\frac{x ^{3}}{3}]_{0}^{310}

Compute the boundaries:

\frac{10}{3}

= \frac{10}{3}

\int_{- 1}^{1} (- 30 x^{2} + 4 x y) d y

\int_{0}^{5} t^{2} + 2 t - 15 d t

\int_{0}^{2} \frac{1}{( 2 - x ) ^{\frac{5}{2}}} d x

\int_{2}^{4} (2 x) d x

\int_{- 2}^{1} (2 x^{3} + 4 x^{2} - x + 3) d x

What is the integral from 0 to \sqrt[3]{10 of}x^2 ?
The integral from 0 to \sqrt[3]{10 of}x^2 is 10/3