What is the integral from 1 to infinity of x/(x^2+8) ?

The integral from 1 to infinity of x/(x^2+8) is diverges

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integral from 1 to infinity of x/(x^2+8)

\int_{1}^{\infty} \frac{x}{x ^{2} + 8} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{x}{x ^{2} + 8} d x

Compute the indefinite integral:

\int \frac{x}{x ^{2} + 8} d x = \frac{1}{2} ln x^{2} + 8 + C

Compute the boundaries:

\int_{1}^{\infty} \frac{x}{x ^{2} + 8} d x =

diverges

= diverges

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What is the integral from 1 to infinity of x/(x^2+8) ?
The integral from 1 to infinity of x/(x^2+8) is diverges