What is the integral from 1 to e of x^{-1} ?

The integral from 1 to e of x^{-1} is 1

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integral from 1 to e of x^{-1}

\int_{1}^{e} x^{- 1} d x

1

Solution steps

\int_{1}^{e} x^{- 1} d x

Use the common integral:

\int x^{- 1} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{1}^{e}

Compute the boundaries:

1

= 1

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What is the integral from 1 to e of x^{-1} ?
The integral from 1 to e of x^{-1} is 1