What is the integral from 0 to 1 of 2/5 (x+2) ?

The integral from 0 to 1 of 2/5 (x+2) is 1

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integral from 0 to 1 of 2/5 (x+2)

\int_{0}^{1} \frac{2}{5} (x + 2) d x

1

Solution steps

\int_{0}^{1} \frac{2}{5} (x + 2) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{5} \cdot \int_{0}^{1} x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{2}{5} (\int_{0}^{1} x d x + \int_{0}^{1} 2 d x)

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} 2 d x = 2

= \frac{2}{5} (\frac{1}{2} + 2)

Simplify

\frac{2}{5} (\frac{1}{2} + 2) : 1

= 1

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What is the integral from 0 to 1 of 2/5 (x+2) ?
The integral from 0 to 1 of 2/5 (x+2) is 1