What is the integral from 0 to 1 of sqrt(1/x) ?

The integral from 0 to 1 of sqrt(1/x) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of sqrt(1/x)

\int_{0}^{1} \frac{1}{x} d x

2

Solution steps

\int_{0}^{1} \frac{1}{x} d x

Simplify

\frac{1}{x} : \frac{1}{x}

= \int_{0}^{1} \frac{1}{x} d x

Simplify

= \int_{0}^{1} \frac{1}{x} d x

Apply the Power Rule

= [2 x^{\frac{1}{2}}]_{0}^{1}

Apply radical rule:

a^{\frac{1}{n}} = n a

= [2 x]_{0}^{1}

Compute the boundaries:

2

= 2

\int_{1}^{2} \frac{x ^{2}}{x ^{3} - 8} d x

\int_{0}^{1} (3 x^{e} + 7 e^{x}) d x

\int_{0}^{\frac{2}{3}} x^{2} (1 - 3 x)^{5} d x

\int_{0}^{e^{2}} ln (x) d x

\int_{0}^{1} \frac{3}{x ^{2} + 1} d x

What is the integral from 0 to 1 of sqrt(1/x) ?
The integral from 0 to 1 of sqrt(1/x) is 2