What is the integral from 0 to x of 1/25 x ?

The integral from 0 to x of 1/25 x is (x^2)/(50)

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integral from 0 to x of 1/25 x

\int_{0}^{x} \frac{1}{25} x d x

\frac{x ^{2}}{50}

Solution steps

\int_{0}^{x} \frac{1}{25} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{25} \cdot \int_{0}^{x} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{x}

= \frac{1}{25} [\frac{x ^{2}}{2}]_{0}^{x}

Compute the boundaries:

\frac{x ^{2}}{2}

= \frac{1}{25} \cdot \frac{x ^{2}}{2}

Simplify

= \frac{x ^{2}}{50}

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What is the integral from 0 to x of 1/25 x ?
The integral from 0 to x of 1/25 x is (x^2)/(50)