What is the sum from n=0 to infinity of 2^{(3-2n)} ?

The sum from n=0 to infinity of 2^{(3-2n)} is converges

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sum from n=0 to infinity of 2^{(3-2n)}

n = 0 \sum \infty 2^{(3 - 2 n)}

converges

Solution steps

n = 0 \sum \infty 2^{3 - 2 n}

Apply Series Ratio Test:

converges

= converges

x = 1 - y^{2}, x = y^{2} - 1

\frac{1 - t ^{2}}{( 1 + t ^{2} ) ^{2}}

x \to 2 lim ((2 x + 5)^{x - 3})

\frac{6 x}{x + 5}, at x = - 3

\int_{- 1}^{1} 0 d x

What is the sum from n=0 to infinity of 2^{(3-2n)} ?
The sum from n=0 to infinity of 2^{(3-2n)} is converges