What is the integral from 1 to 9 of 2/t ?

The integral from 1 to 9 of 2/t is 4ln(3)

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integral from 1 to 9 of 2/t

\int_{1}^{9} \frac{2}{t} d t

4 ln (3)

Decimal

4.39444 \dots

Solution steps

\int_{1}^{9} \frac{2}{t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{9} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= 2 [ln ∣ t ∣]_{1}^{9}

Compute the boundaries:

2 ln (3)

= 2 \cdot 2 ln (3)

Simplify

= 4 ln (3)

\int_{- 4}^{8} (10 - x) d x

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\int_{3}^{5} x 1 + x^{2} d x

\int_{0}^{2} 4 e^{- x} d x

What is the integral from 1 to 9 of 2/t ?
The integral from 1 to 9 of 2/t is 4ln(3)