What is the integral from (3pi)/2 to 2pi of cos(x) ?

The integral from (3pi)/2 to 2pi of cos(x) is 1

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integral from (3pi)/2 to 2pi of cos(x)

\int_{\frac{3 π}{2}}^{2 π} cos (x) d x

1

Solution steps

\int_{\frac{3 π}{2}}^{2 π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{\frac{3 π}{2}}^{2 π}

Compute the boundaries:

1

= 1

\int_{0}^{1} \frac{x}{( x + 31 ) ^{2}} d x

\int_{0}^{2} 3 e^{x^{2} - 3 x} d x

\int_{0}^{4} x^{3} 16 - x^{2} d x

\int_{1}^{5} \frac{1}{x - p} d x

\int_{0}^{x} x^{5} e^{- x} d x

What is the integral from (3pi)/2 to 2pi of cos(x) ?
The integral from (3pi)/2 to 2pi of cos(x) is 1