What is the integral from-2 to 1 of (x^2) ?

The integral from-2 to 1 of (x^2) is 3

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integral from-2 to 1 of (x^2)

\int_{- 2}^{1} (x^{2}) d x

3

Solution steps

\int_{- 2}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 2}^{1}

= [\frac{x ^{3}}{3}]_{- 2}^{1}

Compute the boundaries:

3

= 3

\int_{1}^{4} 2 π x (1 + x) d x

\int_{- 1}^{0} \frac{1}{x} d x

\int_{1}^{4} 10 x d x

\int_{0}^{2} 2 sin (\frac{π x}{2}) d x

\int_{0}^{10} \frac{1}{2} x d x

What is the integral from-2 to 1 of (x^2) ?
The integral from-2 to 1 of (x^2) is 3