What is the integral from 0 to 9 of 4x ?

The integral from 0 to 9 of 4x is 162

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integral from 0 to 9 of 4x

\int_{0}^{9} 4 x d x

162

Solution steps

\int_{0}^{9} 4 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{9} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{9}

= 4 [\frac{x ^{2}}{2}]_{0}^{9}

Compute the boundaries:

\frac{81}{2}

= 4 \cdot \frac{81}{2}

Simplify

= 162

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