What is the integral from-infinity to-3 of θe^θ ?

The integral from-infinity to-3 of θe^θ is -4/(e^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to-3 of θe^θ

\int_{- \infty}^{- 3} θ e^{θ} d θ

- \frac{4}{e ^{3}}

Decimal

- 0.19914 \dots

Solution steps

\int_{- \infty}^{- 3} θ e^{θ} d θ

Compute the indefinite integral:

\int θ e^{θ} d θ = e^{θ} θ - e^{θ} + C

Compute the boundaries:

\int_{- \infty}^{- 3} θ e^{θ} d θ = - \frac{4}{e ^{3}} - 0

= - \frac{4}{e ^{3}} - 0

Simplify

= - \frac{4}{e ^{3}}

\int_{0}^{5} \frac{13}{x + 4} d x

\int_{0}^{\frac{3 π}{4}} \frac{1}{1 + 9 x ^{2}} d x

\int_{- 1}^{1} (x - 1) 1 - x^{2} d x

\int_{0}^{π} (π - x) \cdot cos (n x) d x

\int_{- L}^{0} - x^{2} sin (\frac{nπ x}{L})

What is the integral from-infinity to-3 of θe^θ ?
The integral from-infinity to-3 of θe^θ is -4/(e^3)