What is the integral from 0 to pi of sin^2(x)sin(x) ?

The integral from 0 to pi of sin^2(x)sin(x) is 4/3

Popular >

integral from 0 to pi of sin^2(x)sin(x)

\int_{0}^{π} sin^{2} (x) sin (x) d x

\frac{4}{3}

Decimal

1.33333 \dots

Solution steps

\int_{0}^{π} sin^{2} (x) sin (x) d x

Rewrite using trig identities

= \int_{0}^{π} (1 - cos^{2} (x)) sin (x) d x

Apply u-substitution

: \int_{1}^{- 1} - 1 + u^{2} d u

= \int_{1}^{- 1} - 1 + u^{2} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 1}^{1} - 1 + u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (- \int_{- 1}^{1} 1 d u + \int_{- 1}^{1} u^{2} d u)

\int_{- 1}^{1} 1 d u = 2

\int_{- 1}^{1} u^{2} d u = \frac{2}{3}

= - (- 2 + \frac{2}{3})

Simplify

- (- 2 + \frac{2}{3}) : \frac{4}{3}

= \frac{4}{3}

\int_{- π}^{π} sin (m) x sin (n) x d x

\int_{1}^{4} (\frac{9}{x} - e^{- x}) d x

\int_{0}^{3} 8 - 2 x d x

\int_{0}^{3} \frac{6 x}{1 + x ^{2}} d x

\int_{1}^{3} 10 x (x - 1)^{3} d x

What is the integral from 0 to pi of sin^2(x)sin(x) ?
The integral from 0 to pi of sin^2(x)sin(x) is 4/3