What is the integral from 0 to 1 of sqrt(x^3) ?

The integral from 0 to 1 of sqrt(x^3) is 2/5

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integral from 0 to 1 of sqrt(x^3)

\int_{0}^{1} x^{3} d x

\frac{2}{5}

Decimal

0.4

Solution steps

\int_{0}^{1} x^{3} d x

x^{3} = x^{\frac{3}{2}},

assuming

x \geq 0

= \int_{0}^{1} x^{\frac{3}{2}} d x

Apply the Power Rule

: [\frac{2}{5} x^{\frac{5}{2}}]_{0}^{1}

= [\frac{2}{5} x^{\frac{5}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{5}

= \frac{2}{5}

\int_{- 1}^{2} k x^{2} d x

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\int_{2}^{1} sin (x) d x

\int_{0}^{2 x + y} 1 d z

\int_{0}^{2} 1 + (e^{x})^{2} d x

What is the integral from 0 to 1 of sqrt(x^3) ?
The integral from 0 to 1 of sqrt(x^3) is 2/5