What is the integral from 0 to 3 of x^2cos(x) ?

The integral from 0 to 3 of x^2cos(x) is 7sin(3)+6cos(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of x^2cos(x)

\int_{0}^{3} x^{2} cos (x) d x

7 sin (3) + 6 cos (3)

Decimal

- 4.95211 \dots

Solution steps

\int_{0}^{3} x^{2} cos (x) d x

Apply Integration By Parts

: [x^{2} sin (x) - \int 2 x sin (x) d x]_{0}^{3}

= [x^{2} sin (x) - \int 2 x sin (x) d x]_{0}^{3}

\int 2 x sin (x) d x = 2 (- x cos (x) + sin (x))

= [x^{2} sin (x) - 2 (- x cos (x) + sin (x))]_{0}^{3}

Compute the boundaries:

7 sin (3) + 6 cos (3)

= 7 sin (3) + 6 cos (3)

\int_{0}^{1} x^{3} (x - \frac{1}{2}) d x

\int_{0}^{4} x (x - 2) (x - 4) d x

\int_{0}^{2} 2 t \cdot e^{t^{2}} d t

\int_{0}^{4} \frac{x}{x + 9} d x

\int_{0}^{10} \frac{5}{10 - x} d x

What is the integral from 0 to 3 of x^2cos(x) ?
The integral from 0 to 3 of x^2cos(x) is 7sin(3)+6cos(3)