What is the integral from 2 to infinity of y^{-3} ?

The integral from 2 to infinity of y^{-3} is 1/8

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integral from 2 to infinity of y^{-3}

\int_{2}^{\infty} y^{- 3} d y

\frac{1}{8}

Decimal

0.125

Solution steps

\int_{2}^{\infty} y^{- 3} d y

Compute the indefinite integral:

\int y^{- 3} d y = - \frac{1}{2 y ^{2}} + C

Compute the boundaries:

\int_{2}^{\infty} y^{- 3} d y = 0 - (- \frac{1}{8})

= 0 - (- \frac{1}{8})

Simplify

= \frac{1}{8}

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What is the integral from 2 to infinity of y^{-3} ?
The integral from 2 to infinity of y^{-3} is 1/8