What is the integral from 0 to 0 of sqrt(16-x^2) ?

The integral from 0 to 0 of sqrt(16-x^2) is 0

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integral from 0 to 0 of sqrt(16-x^2)

\int_{0}^{0} 16 - x^{2} d x

0

Solution steps

\int_{0}^{0} 16 - x^{2} d x

\int_{a}^{a} f (x) d x = 0, a \neq = \infty

= 0

\int_{- 1}^{0} \frac{3 x}{( 2 + x ^{2} ) ^{4}} d x

\int_{0}^{t} (y (u) - u) d u

\int_{0}^{9} π (2 x)^{2} d x

\int_{- 1}^{1} (r + 1)^{2} d r

\int_{0}^{3} \frac{2}{9} x d x

What is the integral from 0 to 0 of sqrt(16-x^2) ?
The integral from 0 to 0 of sqrt(16-x^2) is 0