What is the integral from 0 to 2 of sin(t^2) ?

The integral from 0 to 2 of sin(t^2) is sqrt(pi/2)\S(sqrt(2/pi)*2)-sqrt(pi/2)\S(sqrt(2/pi)*0)

Popular >

integral from 0 to 2 of sin(t^2)

\int_{0}^{2} sin (t^{2}) d t

\frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 0)

Solution steps

\int_{0}^{2} sin (t^{2}) d t

Use the nonelementary integral:

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x)

= [\frac{π}{2} § (\frac{2}{π} t)]_{0}^{2}

Compute the boundaries:

\frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 0)

= \frac{π}{2} § (\frac{2}{π} \cdot 2) - \frac{π}{2} § (\frac{2}{π} \cdot 0)

\int_{0}^{3} 5 (1 - e^{x}) d x

\int_{0.2}^{1} \frac{sin ( x )}{x} d x

\int_{0}^{x} \frac{1 + x}{1 - x} d x

\int_{1}^{8} 1 + 3 m d m

\int_{- 1}^{4} \frac{1}{( x + 2 ) ( x + 1 )} d x

What is the integral from 0 to 2 of sin(t^2) ?
The integral from 0 to 2 of sin(t^2) is sqrt(pi/2)\S(sqrt(2/pi)*2)-sqrt(pi/2)\S(sqrt(2/pi)*0)